- Theorem: The proportion in which sugar at Rs. x per kg must be mixed with rice at Rs. y per kg, so that the mixture be worth Rs. z a kg, is given by
= ( y - z ) z - x - Example :
- Detail Method : Let the required ratio be x. y.
As per Question,
310x + 360y = 325(x+y)
or 310x + 360y = 325x + 325y
325x - 310x = 360y - 325y
150x = 350y
15x = 35y
3x = 7y= x : 7 y 3 - Ailigation Method : By the rule of alligation we have :
C.P.of 1 kg cheaper sugar C.P.of 1 kg dearer sugar (310 paise) Mean price
(325 paise)(360 paise) 35 15
so, they must be mixed in the ratio of = 7 : 3 - Quicker Method : Here you can use direct formula :
= ( y - z ) z - x = ( CP of dearer - Mean Price ) Mean Price - CP of cheaper = ( 3.60 - 3.25 ) = ( 0.35 ) 3.25 - 3.10 0.15
Direct Formula / Rule 1 :
The proportion in which sugar at Rs. 3.10 per kg must be mixed with sugar at Rs. 3.60 per kg, so that the mixture be worth Rs. 3.25 a kg ?
- Exercise :
- In what proportion must rice at Rs 21 per kg be mixed with rice at Rs 28 per kg, so.that the mixture be worth Rs. 25 a kg ?
- In what ratio, must coffee at Rs. 62 per kg Is mixed With coffee at Rs. 72 per kg so that the mixture must be worth RS. 64.50 per kg ?
- In what ratio must water be mixed with oil costing Rs. 12 per litre to obtain a mixture worth of Rs. 8 per litre ? Answers :
1 = 5 : 4, 2 = 3 : 1, 3 = 1 : 2
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