- Theorem: The proportion in which water must be mixed with spirit to gain or to lose x% by selling it at cost price is given by
= ( x ) 100 - Example :
- Detail Method : Let the required proportion of water to spirit be a : b and the cost price of spirit be Rs x per litre.
As per the question,
Selling price of the mixture = Rs x per litre.
Cost price of the mixture= x X 100 x X 100 100 = Rs 6x = per litre. 7 ∴ (a X 0 + b X x) = (a + b) 6x 7 or, bx = (a + b) = 6 x 7 or, b ( 1 - 6 ) = 6a 7 7 or, b = 6a 7 7 or, a = 1 b 6 - Ailigation Method :
Let CP of sprit be Re 1 per litre.
Then SP of 1 litre o f mixture = Rs 1.Gain = 16 2 % 3 CP of 1 litre of mixture = Rs ( 100 X 3 X 1 ) = Rs 6 350 7 CP of 1 litre water CP of 1 litre pure spirit (Rs 0) Mean price
Rs 6/7(Rs 1) 1/7 6/7 Quantity of water = 1/7 = 1 Quantity of spirit 6/7 6 - Quicker Method : Here you can use direct formula :
the required proportion = 50 = 1 : 6 300
Direct Formula / Rule 4 :
In what proportion must water be mixed with spirit to gain 16 2/3 % by selling it at cost price?
- Exercise :
- In what proportion must water be mixed with spirit to gain 33
1/3 %by selling it at cost price? - In what proportion must water be mixed with spirit to gain 16% by selling it at cost price?
- In what proportion must water be mixed with spirit to gain 25% by selling it at cost price? Answers : 1 = 1 : 3, 2 = 4 : 25, 3 = 1 : 4
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